Use the definition of the derivative to find the derivative of f (x) at the indicated point: f(x)=x^2-x at x=3
Show me your best guess or where you get stuck. There's no point in me explaining the entire thing when I'm sure you can do some of it already.
f(x)=x^2-x differentiate w.r.t x df(x)\dx= d\dx (x^2 -x) by appling power function d\dx x^n = nx^n-1 df(x)\dx = 2x -1.........eq#1 now put x =3 in eq#1 =2(3)-1 = 6-1 df(x)\dx =5
this is the correct answer
I am supposed to use: f ' (x) = ( f (x+h) - f (x) )/ h as h approaches zero
Yeah, I don't know what @Haseeb96 is doing, I think he needs a nap. lol So malibu, you know what to use, show me your steps. I'll help you along, but only if you make an effort and guess.
I think i got it, how to do it. The answer is 5.
But I did it differently. I mean the setup too.
You should have done it with the definition, so if you mean you did it differently than Haseeb then yeah, that's great. Otherwise, it's wrong.
Yes I used f'(x)=lim h approaches 0 f(x+h)-f(x)/h
then put the given x=3 in the given answer
But thanks, @Haseeb and @Kainui.
At least you have the quick shortcut to taking the derivative so that you can check yourself! Always check yourself on "definition of a derivative" questions since it's so easy!
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