Find the slope of the tangent line to the graph of f at the given point. f(x) = x^2 + 5x at (4, 36)
That is the same as finding the derivative of the function at \(x=4\)
how can i solve it
Firstly, can you find the derivative of \(f(x)\)? :)
how?
Are you taught differentiation? :)
no
@hartnn That's interesting
you'll only need one formula of derivative here. \(\large \dfrac{d}{dx}x^n = n x^{n-1}\)
so, can you find derivative of x^2 ? plug in n=2 in the formula
@hartnn how can i find derivative of x^2 ?... Could you help me out trough
@hartnn Is there anyway to calculate tangent without calculus? :o
i don't think so we can find the value of x for which the function is max or min, but slope of tangent.....we'll need derivative this question does belong to derivative topic right ? if not, then which topic ?limits?
Yes the topic is derivative
so you should have that formula which i gave you anyways, to find derivative of x^2 you'll just have to put n=2 in that formula what do u get ?
and what does d stand for
\(\dfrac d{dx}\) is an expression meaning "differentiate"
yes dx is the change in variable 'x' d f(x) is the change in function of x so, df(x)/dx is the change in function, with respect to change in x which we call as derivative of f(x)
so what digit is d for... i am stuck
\(\large \dfrac{d}{dx}x^n = n x^{n-1}\) put n=2 there what do u get ?
\[\frac{ d }{ dx }4^{2}=2(4)^{2-1}\]
why did u put x= 4 :O you'll only get d/dx (x^2) = 2x right ?
yes
using same formula can you tell me derivative of x ?
hint : x means x^1, so put n=1 in that formula
2x
try again :)
x^2
2x was the derivative of x^2 to get the derivative of 'x', plug in n=1 in that formula what u get if u put n=1 there?
\[\frac{ d }{ dx }x ^{1} =1x ^{1-1}\]
yes 1x^0 and whats x^0 =... ?
0
no...x^0 is just =1 so derivative of x just =1 got this?
yup at last i got it
good! so now try to find the derivative of x^2+5x ?
Note : constants can be taken out of the derivative so d/dx (5x) = 5 d/dx (x)
oka moment
then
could you find derivative of x^2+5x ? = derivative of x^2 + 5 derivative of x =. ...?
0 right
no how? we just found derivative of x^2 and derivative of x right ?
sory derivative of x is 1
yes, and derivative of x^2 ?
its 1 again
no... we found that derivative of x^2 =2x , right ? by putting n=2 in the formula
ohh yes that right
could you find derivative of x^2+5x ? = derivative of x^2 + 5 derivative of x =. ...?
derivative of x^2+5x is 7x right
why 7x ?
2x + 5x = 7x
2x is correct but not 5x 5 * derivative of x = 5*1 =5 got this?
ohh
because derivative of x is 1 !
ohh ok
so derivative of x^2+5x = 2x+5 right?
yes
so we go ahead and put the value of x and solve right
so the slope of tangent at 4,36 is the derivative of graph at 4,36 so just put x=4 in your derivative yes, right!
13 is the answer right
absolutely :)
woooo.. that was long steps for 1 question... U deserve more than medal @hartnn
thnxs alot @hartnn
don't worry for steps, once you have enough practice, you'll be able to solve derivatives questions mentally ;) you're welcome ^_^
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