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Nitrogen and hydrogen combine at high temperature, in the presence of a catalyst, to produce ammonia. N2(g)+3H2(g)=2NH3(g) Assume 0.280 mol of N2 and 0.884 mol of H2 are present initially. After complete reaction, how many moles of ammonia are produced?__________ How many moles of H2 remain?___________ How many moles of N2, remain?___________ What is the limiting reactant?________(nitrogen or hydrogen)
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according to equation 1 moleof N2 gives 2 mole of ammonia 0.28 mole of N2 gives =2*0.28/1
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