Question

Calculate the derivative of y=4log(base3)(x^2-1)

Answer 1

\[differentiate y=\log_{3} (x ^{2}-1)\]

Answer 2

using log_b(z) = log(z)/log(b)
y={4log(x^2-1)}/log3
y'=(4/log3)(2x)/(x^2-1) as derivative of log(x^2-1)=2x/x^2-1
y'=8x/(x^2-1)log3

Answer 3

im kind of confused can you further help me?

Answer 4

the change of base formula.

log(base)(argument) = log(argument) / log(base)
standard-base log of the argument) divided by (same-standard-base log of the non-standard-base)
i use this formula than take derivative, as 4/log3 is constant and derivative of log(x^2-1) is 2x/(x^2-1)
i hope u understand