Question

Calculus Question

Answer 1

f(x)=In[(x+1)(x+2)], then \[f \prime(x)\]

Answer 2

=

Answer 3

Multiply out brackets then use the chain rule.

Answer 4

Let u = x^2 +3x +2

then dy/dx = ln[u] 1/u

so you then have

d/dx(x^2 +3x +2)/(x^2 +3x +2)

= (2x +3)/(x^2 +3x +2)

Does this make sense?

Answer 5

kind of

Answer 6

Your just using the chain rule, so essentially your starting with with the outer most function and working way in to the innermost function.

Answer 7

ok

Answer 8

Also when I took the first derivative there was a typo is should be dy/du of ln[u] = 1/u.

Answer 9

I hope this helps you out :)

Answer 10

Remember with the chain rule you start with the derivative of the outermost function and then work your way inward in a sense, multiplying the next derivative by the derivatives of the preceding function.

Answer 11

It should be *functions at the end :)