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Do you believe there is a finite, closed-form solution? I don't.
yes, it was in the test and i had no clue.
Were there finite limits?
yep from y^(1/4) to 2
\(x = y^{1/4}\;or\;y = x^{4}\)? A double integral? Can we exchange the order of the integration?
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ya it is iterated integral, we can surely exchange but no clue how
alright lemme just right the real question instead of just first part
\[\int\limits_{0}^{16}\int\limits_{x^\frac{ 1 }{ 4 }}^{2} \frac{ 1 }{ 1+y^5 } dy dx\]
\(y = x^{1/4}\) is monotonic on [0,16]. It should be relatively easy. \(\int\limits_{0}^{2}\;\int\limits_{0}^{y^{4}}\dfrac{1}{1+y^{5}}\;dx\;dy\) How's that? Did we cover the same area?
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