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Find dy/dx by implicit differentiation.
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\[x^2y+y^2x=−2\]
first take derivative of each x and y and wherever you take the derivative of a "y-func" throw in a dy/dx. Don't forget product rule.
2x*y+1(dy/dx)*x^2+2y(dy/dx)*x+y^2*x=-2
then solve for dy/dx
I got (2xy+2+y^2*x)/(-x^2-2*y*x)
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That's the answer???
yep.
wait. No it isn't
I messed up. I didn't take the derivative of (-2). So now I got -(2xy+y^2)/(x^2+2xy). (I also had another mistake)
it's (-2xy-y^2)/(x^2+2xy)
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