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Mathematics 13 Online
OpenStudy (anonymous):

Find dy/dx by implicit differentiation.

OpenStudy (anonymous):

\[x^2y+y^2x=−2\]

OpenStudy (anonymous):

first take derivative of each x and y and wherever you take the derivative of a "y-func" throw in a dy/dx. Don't forget product rule.

OpenStudy (anonymous):

2x*y+1(dy/dx)*x^2+2y(dy/dx)*x+y^2*x=-2

OpenStudy (anonymous):

then solve for dy/dx

OpenStudy (anonymous):

I got (2xy+2+y^2*x)/(-x^2-2*y*x)

OpenStudy (anonymous):

That's the answer???

OpenStudy (anonymous):

yep.

OpenStudy (anonymous):

wait. No it isn't

OpenStudy (anonymous):

I messed up. I didn't take the derivative of (-2). So now I got -(2xy+y^2)/(x^2+2xy). (I also had another mistake)

OpenStudy (anonymous):

it's (-2xy-y^2)/(x^2+2xy)

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