Let log P/N = 5 , and log M/N = 9 , What is the relationship between P and M?
Subtract log M/ N by log P/N
is log the natural log?
no the log as in 10 .
How do I do that ash? My knowledge with logs is little ..
ok \[\log \frac M N - \log \frac P N =9-5\] Can you simplify this a bit? maybe the right side
Yeah, 4 on the right side
According to subtraction property of log \[\log A -\log B= \log \frac A B\] Can you use that here? @shamil98
log M/N = log M - log N log P/N = log P - log N
treat M/ N as A P/N as B then use it to reduce two terms to one
never mind that would work as well, substitute your expansion and see if any terms get cancelled.
\[ \frac P N = 10^5 \\ \frac M N = 10^9 \\ \frac {\frac P N} {\frac M N}= \frac {10^5}{10^9}\\ \frac {P}{M}=\frac{1}{10^4} \]
Log M - log N - ( log P - log N ) = 4 Log M - log N - log P + log N = 4 Log M - Log P = 4
yes, now use the sub property to combine log m and log p
log M/P = 4
@eliassaab Sir please don't directly handover the answers to the asker. It won't help them.
good shamil. Do you know how log is defined?
Nope.. could you explain?..
ok, so we have \[\log_A B=C\] this implies \[B=A^C\] A=base that's how log is defined Suppose we have \[\log_2 4=C\] so \[2^C=4\] or \[C=2\] Do you follow?
Yeah.
can you apply it here?
log M/P = 4 \[\log_{10} \frac{ M }{ P } = 4\] \[\large \frac{ M }{ P } = 10^4\] ?
yes, good work. You can simplify it
\[\large \frac{ M }{ P } = 10000\] \[\large M = 10000P\]
yes, that's right
thanks, for the explanation. I appreciate @eliassaab your effort, I just needed an explanation on how to get to there.
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