Question

Given that log_7(t) = 14.07, log_7(x) = -10.8, and log_7(z) = -17.02, find the following:

log_7(tx^11)

Answer 1

Remember these rules:

\( \log (ab) = \log + \log b\)

\(\log a^n = n \log a\)

Now we apply those rules:

\( \log_7 (tx^{11}) \)

\(= \log_7 t + \log_7 x^{11} \)

\(= \log_7 t + 11 \log_7 x\)

Now just substitute the values of you have for the logs and evaluate.