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write 27^-2/3 in radical notation. Evaluate radical expression
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\[\huge \sqrt[n]{x^m} = x^\frac{ m }{ n }\]
Write 27 as 3^3 and simplify.
\[\huge x^{-n} = \frac{ 1 }{ x^n }\]
So using these formulas you know that this is : \[\huge \frac{ 1 }{ \sqrt[3]{27^2} }\]
From there just simplify.
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I am horrible at this stuff. It looks like gibrish to me. so if i do 3^3 and that equals 27 its my answer?
\[\huge \frac{ 1 }{ \sqrt[3]{27^2} } = \frac{ 1 }{ \sqrt[3]{729} }\] Just simplify it.
What value multiplied by itself results in 729?..
by itself three times*
9
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Correct. So your resulting evaluated radical is \[\huge \frac{ 1 }{ 9 }\]
that makes more sense now. thankyou
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