Question

Can someone help me balance the following reaction:
MnO4- +e- + H+ => Mn2+ + H20

Answer 1

The balanced half-equation should be:
Mn(7+)O4(2-) + 6H(1+) + 11e(1-) ==> Mn(2+)O(2-) + H2(1+)O(2-)
You need 6 H+ to create water and 11 e- to reduce the hydrogen and the manganese.

Answer 2

Thank you so much! I really appreciate it! :)

Answer 3

Welcome:)