Question

The slope of a line is 11 and the point (14,19) is on the line. Express the line in slope- intercept form

Answer 1

Slope intercept form is

\[\large y = mx + b\]

where m = slope
b = the y-intercept

What you are given is a slope (m)...and a point...(x,y)

so we are potentially solving for the y-intercept here

plug in everything...

\[\large 19 = 14(11) + b\]

can you solve for 'b' ?

Answer 2

the formula is
y-y1+m(x-X1)

Answer 3

If you want to use that, thats fine too...that is point-slope form though...

so if you want to set it up like that...

\[\large y - 19 = (11)(x - 14)\]

Now just rearrange and solve for 'y'

Answer 4

im confused

Answer 5

m=slope

Answer 6

Alright...so there were 2 ways to solve this...you could do the way I posted above...but you were also right in saying that you can use point slope form to solve this...either way will come out to the same answer

Answer 7

so lets use your point slope form equation

\[\large y - y_1 = m(x - x_1)\]

Answer 8

You have a point....(14,19) this will be your (x1,y1) and you have a slope...this will be your 'm'

Answer 9

i got
y-19+11x-154

Answer 10

m=slope so plug the slope into the m slot.

Answer 11

Right @Kyria just remember it should be y - 19 = 11x - 154

the minus sign does not go away

\[\large y - 19 = 11(x - 14)\]
becomes
\[\large y - 19 = 11x - 154\]


Now you want y by itself...so what do you do to that 19?

Answer 12

y=11x+173

Answer 13

Correct

Answer 14

Close...but remember it is -154 + 19...

Answer 15

-135

Answer 16

Right...so it is

\[\large y = 11x - 135\]

Answer 17

Great job @Kyria

Answer 18

thanks i may need yhu help again

Answer 19

stay in touch

Answer 20

No problem, If I'm not on your question feel free to tag me or message me :)

Answer 21

thanks