Question

Please help solving this for a medal?

Answer 1

what!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answer 2

\[\frac{ 1 }{ x^2-7x+10}=\frac{ x }{ x-5 }+\frac{ 1 }{x-2}\]

Answer 3

IDK!!!!!!!!!!!!!!!!!!!!!!! srry :(

Answer 4

can u help me- is that y ur on my page?

Answer 5

Add the two fractions together first :)

Answer 6

Don't I have to find a common denominator first though?

Answer 7

@nannaberry what are you talking about?

Answer 8

@bruno102 yep

Answer 9

How do you find it?

Answer 10

u were on my page- I thought you were going to help me

Answer 11

:)

Answer 12

are you sure? I didn't purposely go to your page...@nannaberry anyway srry

Answer 13

thts ok- dont be srry

Answer 14

do u guys kno anyone in CA

Answer 15

connections

Answer 16

Nope, I'm in keystone

Answer 17

well gotta go :(

Answer 18

well hope you find someone to help you @nannaberry bye

Answer 19

thanks ;)

Answer 20

Yep

Answer 21

:)

Answer 22

\[\frac{ 1 }{ x ^{2}-7x+10 }=\frac{ x }{ x-5 }+\frac{ 1 }{ x-2 }\]
\[\frac{ 1 }{ x ^{2}-7x+10 }=\frac{ x(x-2) }{ x-5 }+\frac{ 1(x-5) }{ x-2 }\]
\[\frac{ 1 }{ (x-5)(x-2) }=\frac{ x ^{2}-x-5 }{ (x-5)(x-2) }\]
\[1=x ^{2}-x-5\]
\[0=x ^{2}-x-6\]
\[0=(x-3)(x+2)\]
\[x=3 \]
\[x=-2\]

Answer 23

In the second line were you cross multiplying?

Answer 24

ya

Answer 25

I don't understand what you did in the third line..

Answer 26

You need to review how to add two things with different denominators. Finding a common denominator is an important thing to understand. Simple example: 1/2 + 1/3. You multiply the top and bottom of the first fraction by 3. Then you multiply the top and bottom of the second fraction by 2. Now if you re-write it, you have 3/6 + 2/6 and you can now add them. I wouldn't call it cross multiplying.

Answer 27

On the left hand side of the third line, the person factored the denominator.

Answer 28

On the right hand side of line 2, it's not written correctly. Start from the beginning and write it on paper. Let's look at the right side first. Multiply the top and bottom of the first fraction by (x-2). Then multiply the top and bottom of second fraction by (x-5).

Answer 29

Ok I think I did that

Answer 30

Now you're ready to add two things that have the same denominator of (x-2)(x-5).
Keep in mind that if you multiply something by x/x or (x-2)/(x-2), you're not changing the thing. It's like multiplying it by the number one.

Answer 31

thanks @jam333 , that was i mean @bruno102

Answer 32

Ok

Answer 33

Just a question, is this question normal to be having in just 9th grade?

Answer 34

@jam333

Answer 35

Like is it a normal concept to be learning in this grade?

Answer 36

@tblue1998 is this type of question normal to be learning about in 9th grade?

Answer 37

yeah, i think this type of question is normal for 9th grade..

Answer 38

Oh, does it have to do with algebra 2 because that is what I am in. @tblue1998

Answer 39

Yah

Answer 40

X.X

Answer 41

I know it's a bit of a scary question. Keep in mind that the word 'equation' means that the left side equals the right side. So if 1/x = b/x, can you see how b must equal 1? Common denominators are learned much earlier than grade 9. You are just new at dealing with so many x's. You'll get used to it with practice.

Answer 42

Factoring takes lots of practice. It gets easier so put a bit of time learning the different tricks in factoring. It will make your life easier this year. Grade 9 math is challenging but you can do it!!