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A sealed glass bottle containing air at at- mospheric pressure (101 kPa) and having a volume of 43 cm3 is at 34C. It is then tossed into an open fire. When the temperature of the air in the bot- tle reaches 169C, what is the pressure inside the bottle? Assume any volume changes of the bottle are negligible. Answer in units of kPa
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pV=nRT so p=nRT/V and the ratio of the pressures will be the ratio of the absolute temperatures, as the volume and the amount of gas remain the same. p=(101kPa)(169+273)/(34+273)= (101kPa)(1.44)=145 kPa.
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