Question

Help

Answer 1

@AkashdeepDeb @Luigi0210

Answer 2

Sorry, I am of no help atm :(

Answer 3

okay thanks anyways @jam333 can you help me i know you helped me with the other one are you available?

Answer 4

@Haseeb96 can you help me?

Answer 5

they are both correct due to the mean value thm which says that for a continuous function there is some point "c" in the interval which has same slope as avg slope of interval
\[f'(c) = \frac{f(2) -f(-2)}{2-(-2)}\]

Answer 6

if avg slope is 0 .... then f(2) = f(-2)
also only at a turning point (local max) is the slope zero

Answer 7

ohh okay i undertsadn can you help me with another one?

Answer 8

sure

Answer 9

tahnks :)

Answer 10

@dumbcow hello?

Answer 11

sorry
here is graph and zeros
http://www.wolframalpha.com/input/?i=+x%5E4+%2B2x%5E3%2B6x%5E2-3x+-7%3D0

Answer 12

ohh okay thanks one more ?

Answer 13

@dumbcow