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Mathematics 6 Online
OpenStudy (highschoolmom2010):

find the lateral area of the cone to the nearest whole number

OpenStudy (highschoolmom2010):

OpenStudy (anonymous):

hold on one minute

OpenStudy (anonymous):

the two numbers are 4 and 4.5 right

OpenStudy (highschoolmom2010):

I looked at the wrong problem @Kstate yes

OpenStudy (nurali):

LA = π* r * l To find l : 2^2 + 4.5^2 = l^2 I^2=24.25 I=sqrt(24.25) I=4.92 LA=3.14*2*4.92 LA=30.8 m^2

OpenStudy (highschoolmom2010):

@agent0smith this is the problem

OpenStudy (highschoolmom2010):

says that what @nurali said what incorrect...

OpenStudy (jdoe0001):

\(\bf \textit{Lateral Surface of a Cylinder}=\pi r\sqrt{\textit{slant height}} \) so do you know what the slant height is?

OpenStudy (jdoe0001):

ahemm \(\bf \textit{Lateral Surface of a Cone}=\pi r\sqrt{\textit{slant height}}\) rather

OpenStudy (ranga):

Lateral Surface Area of Cone = pi * R * L where R is radius and L is slant height.\ Is 4m the radius or the diameter in the diagram?

OpenStudy (jdoe0001):

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OpenStudy (highschoolmom2010):

4m is the radius

OpenStudy (highschoolmom2010):

\[4^2+4.5^2=C^2\] \[16+20.25=C^2\] \[36.25=C^2\] \[6 \approx C\]

OpenStudy (highschoolmom2010):

that just doesn't look right

OpenStudy (phi):

I nurali did it correctly. I assume the 4 m is the diameter and the radius is 2 the slant height is \[\sqrt{ \left(\frac{9}{2}\right)^2 + 2^2 } \\ = \frac{\sqrt{97}}{2}\] the lateral area is pi* r* s = \[ 2\pi \cdot \frac{\sqrt{97}}{2} = \pi \sqrt{97}= 30.94 \approx 31\]

OpenStudy (ranga):

Lateral Area = pi * r * l If radius is 4m: A = pi * 4 * sqrt(4^2 + 4.5^2) = 75.7 rounded up to 76 m^2 If diameter is 4m: A = pi * 2 * sqrt(2^2 + 4.5^2) = 30.9 rounded up to 31 m^2

OpenStudy (highschoolmom2010):

ah @phi I understand now & @nurali thanks for the help I just didn't understand really well what you were doing

OpenStudy (nurali):

My Pleasure.

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