how do i find the length of the transverse and conjugate axis of (x-4)^2/36 - (y-2)^2/9=1?

Question

anonymous · Answer

@ranga

amistre64 · Answer

consider when x=4, and also when y=2

only one of them those produces a viable solution ... the under parts tells the length of half the axis

anonymous · Answer

is there a certain equation i would use to find the length of the transverse and conjugate axis?

amistre64 · Answer

(x-4)^2/36 - (y-2)^2/9=1
  ^^^
when this is zero

- (y-2)^2/9=1  has no solution



(x-4)^2/36 - (y-2)^2/9=1
                         ^^^
                    when this is zero

(x-4)^2/36 =1  has 2 solutions ...   we want to observe that 36

amistre64 · Answer

half the transverse axis is equal to sqrt(36)

half the conjugate would be the sqrt(9) by default

amistre64 · Answer

errr, im almost confusing that with an ellipse :/

anonymous · Answer

uh oh :o

amistre64 · Answer

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