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OpenStudy (shamil98):
The formula or rule for this is
\[\huge (a^m)^n = a^{m*n}\]
OpenStudy (mathstudent55):
Also,
\( (abc)^n = a^nb^nc^n \)
OpenStudy (anonymous):
So it'd be \[2n ^{4}h ^{3*4}\] ?
OpenStudy (mathstudent55):
Every factor inside the parentheses, including the 4, is raised to teh 4th power.
OpenStudy (shamil98):
\[\huge 2^4 * n^{4*4} * h^{3*4}\]
My bad.
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OpenStudy (anonymous):
okay, so it would be? \[2^{4}n ^{16}h ^{12}\]
OpenStudy (shamil98):
Yes, but you can simplify 2^4 further.
OpenStudy (anonymous):
2^4 equals 8, so now is that it simplifies to?
OpenStudy (mathstudent55):
You are correct.
\((2n^4h^3)^4\)
Use the second rule first. When a product is raised to a power, raise every factor to that power.
\(= 2^4 \cdot (n^4)^4 \cdot (h^3)^4 \)
Now use the first rule.
\(=16n^{16}h^{12}\)
OpenStudy (anonymous):
Thanks so much :D
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OpenStudy (mathstudent55):
wlcm
OpenStudy (shamil98):
Just to clarify.
2^4 = 16
2 x 2 x 2 x 2 = 16
not 8.