Question

Help please! Dividing Radicals

Answer 1

\[\frac{8}{\sqrt{3} + \sqrt{2}}\]

Answer 2

\[\frac{8 \times (\sqrt{2} - \sqrt{3})}{(\sqrt{2} + \sqrt{3}) \times (\sqrt{2}-\sqrt{3})}\]
the middle term in the denominator is going to cancel and it's just going to be,
\[\frac{8\sqrt{2}-8\sqrt{3}}{2-3}=\frac{8\sqrt{2}-8\sqrt{3}}{-1}\]this can be an answer already but to write it a little better,
\[\frac{8\sqrt{2}-8\sqrt{3}}{-1}=\frac{(8\sqrt{2}-8\sqrt{3}) \times (-1)}{(-1) \times (-1)}\]\[\frac{-8\sqrt{2}+8\sqrt{3}}{1},~~~~~~~or~~~~~~\frac{8\sqrt{3}-8\sqrt{2}}{1}\]

Answer 3

So I would put\[\frac{8\sqrt{3}-8\sqrt{2}}{1}\]as the final answer.

Answer 4

Thank you so much! especially for the explanation

Answer 5

@SolomonZelman

Answer 6

Anytime!