PlEASE CHECK ANSWER! MEDAL WILL BE GIVEN !
Which ordered pair makes the inequality true?
x + 4y 10
(–3, –2)
(–6, 4)
(19, –2)
(14, –1)

Question

PlEASE CHECK ANSWER! MEDAL WILL BE GIVEN !
Which ordered pair makes the inequality true?
x + 4y > 10
       (–3, –2)
       (–6, 4)
       (19, –2)
       (14, –1)

anonymous · Answer

D is my Answer !

jonnyvonny · Answer

So when a solution to an inequality it true, the value that you get after plugging the x-value, would be true at the end:$$x+4y>10\rightarrow y>(10-x)/4$$  
Now we plug in 14.$$y>(10-x)/4\rightarrow y>(10-14)/4\rightarrow y>4/4\rightarrow y>1$$
Now, the y-value in the point we chose was -1; (14,-1). We can substitute the -1 for y, and see if its true:$$y>1\rightarrow -1>1$$
Since this reads as "-1 is greater than 1", is not true, then this is NOT a solution to the inequality.

anonymous · Answer

so there is no answer to this then ? @JonnyVonny

jonnyvonny · Answer

No; I'm saying your answer is wrong, the answer is c; plug it in$$y>(10-x)/4\rightarrow y>(10-19)/4\rightarrow y>-9/4$$
The y value from the point (19,2) is 2. Substitute 2 with y. You'll get "2 is greater than -9/4", which is true, therefore (19,2) is a solution.

anonymous · Answer

oh rahj thanks

jonnyvonny · Answer

Yw, if you need more assisntance with thing, feel free to pst :)