Question

Dividing Radicals Please help I'm still sort of in the dark I mean I get it but I don't get it.

Answer 1

\[4\sqrt{12}=8\sqrt{3}\]

Answer 2

Multiply numerator and denominator by sqrt3

Answer 3

so that would mean \[\frac{ \sqrt3+\sqrt6 }{ 8}\] @Mertsj ?

Answer 4

yes i guess it is thank you so much @Mertsj

Answer 5

\[\frac{3+3\sqrt{2}}{8\sqrt{3}}\times\frac{\sqrt{3}}{\sqrt{3}}=\frac{3\sqrt{3}+3\sqrt{6}}{24}=\frac{\sqrt{3}+\sqrt{6}}{8}\]

Answer 6

Yep. Just like you said.