Question

PL. HELP ME MOMENT OF INERTIA QUESTION

Answer 1

what is the Question

Answer 2

find out the moment of inertia of the following structure (written as PHYSICS) about axis AB and made of thin rods of the mass per unit length lambda

Answer 3

This will be "plug and chug," a grind but doable.

First, the mass of each rod of length l is m = lambda l.

Next, the moment of inertia of the rods lying along A-B is
zero.

The rods that are parallel to A-B but a distance l away each have moments of
m l^2.

The rods of length l touching A-B and perpendicular to it each have moments of
m l^2 /3.

Count those in each category, multiply by the moment of each, then add. Done!

Answer 4

i dont understand how the rods parallel to AB at distance l will have moment of inertia as ml^2 pl. help

Answer 5

wavelength equals speed of light / frquency of oscillation....luckily this is the easiest way to do it if you know calculus, so we do not know frequency but we do know the change in state level which is amplitude. and there is a equation relating frequency and amplitude. frequency times wavelength equals amplitude. so if we rearrange we get frequency equals amplitude divided by wavelength...however we dont know wavelength but we do know the speed of light and plancks constant.. plancks constant is 6.62 x 10 ^-34 the equation to relate the planck and wavelength is wavelegth equals plancks constant divided by speed of light which is 3.00x 10 ^-8 . Use these equatuions to find wavelength Message me back right away so I know you're doing the problem well or if you need any more help... BTW SORRY FOR MISSPELLING TOO LAZY TO CORRECT THEM