Question

Which statement is true about the sum square root of 50 + square root of 6?

It is rational and equal to 2.

It is rational and equal to 8.

It is irrational and equal to 2square root of 2.

It is irrational and equal to 8square root of 2.

Answer 1

@binks

Answer 2

I'm not sure but here is a good video https://www.khanacademy.org/math/arithmetic/exponents-radicals/radical-radicals/v/square-roots-and-real-numbers

Answer 3

thanks so much

Answer 4

\[\sqrt{50}+\sqrt{6}=5\sqrt{2}+\sqrt{6}\]
I can't find it matching to any of the above statements. The above surd cannot be simplified any further

Answer 5

actually the 6 is supposed to be 18 im not sure why it came up as 6 so sorry

Answer 6

haha okay that makes more sense
okay so we have:\[\sqrt{50}+\sqrt{18}=\sqrt{25*2}+\sqrt{9*2}=5\sqrt{2}+3\sqrt{2}\]
just add the coefficients

and if it cannot be expressed as a fraction then it is irrational [hint, a surd is not a fraction]!

Hope that helps!

Answer 7

how do you add all of it?

Answer 8

You just add the coefficients :-)
so:\[5\sqrt{2}+3\sqrt{2} = (5+3)\sqrt{2}= ?\]

Answer 9

so its D right

Answer 10

yup