Question

Given the equations \[9x+\frac{ 3 }{ 4 } y=6 ~and~ 2x+\frac{ 1 }{ 2 }y=9\], by what factor would you multiply the second equation to eliminate y and solve the system through linear combinations?

A) \[-\frac{ 4 }{ 3 }\]

B) \[−\frac{ 3 }{ 4 }\]

C) \[−\frac{ 3 }{ 2 }\]

D) \[−\frac{ 7 }{ 2 }\]

@kelliegirl33 @Salmon

Answer 1

9x + 3/4y = 6
2x + 1/2y = 9
hmmmm.....1/2 * -3/2 = - 3/4

you would multiply by -3/2, which would make the y in the second equation be -3/2.....and this will cause the y's to cancel out.

Answer 2

oops..would make the y in the second equation be -3/4

Answer 3

the answer is -3/2

Answer 4

So the correct answer would be B?

Answer 5

Oh, so C?

Answer 6

yes...C is the answer

Answer 7

Thank you.

Answer 8

YW :)