please help medals will be given how many solutions does the system of equations have? x-14y=12 and 5x -20y=60 one two infinitely many none
two
how many solutions does the system of equations have? y-5x=-6 and 3y-15x =-12 @Haseeb96 what about this one
Those are two parallel lines that never intersect.. so none
@ECE th second one i just posted right ?
there are two methods by which you can solve this system of equation 1. Elimination method 2. substitution method
so the answer is ?
Using the elimination method, I believe you will find there is only one solution that will satisfy the first system. (12,0)
The elimination method is easy enough, Multiply first equation thru by 5, then subtract and solve for y.
two solution
@Haseeb96 other than x=12, and y = 0, what is another solution for the First system? x-14y=12 and 5x -20y=60
that is substitution method in which any one equation you take separate only one variable from the equaation then put in the another equation
Are you saying there is two methods to arrive at two different solutions or arrive at a single solution?????
Using substitution method: x - 14y = 12 x=14y + 12 Substitute in the 2nd equation 5x - 20y = 60 5(14y + 12) - 20y = 60 70y + 60 - 20y=60 50y = 0 y=0, substiution of 0 for y in either of the original equations result in a value of 12 for x The same solution as obtained by the elimination method.
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