A solution of salt and water contains 60 grams of water per 120 milliliters of the solution. If 1 mole of water weighs 16 grams, _____ moles of water would be present in 40 milliliters of the solution. [Round off your answer to two decimal places] Numerical Answers Expected! @TheRealMeeeee @bibby @Dominick
well 60/16 is the moles and 40/120 is a third, i would say the answer of 60/16 mult by a third.
these are ratio problems kind of like this 1mole of water/16 g= x mole of water/60 g = 60/16 = moles of water then that answer/120 ml = how many moles/40 = 40(that answer)/120= how many moles in 40
16 x 3.75 = 60 so 3.75 moles
1g H20 in 2mL soln => 20 g H2O in 40mL soln => 20g/16g/mol Answer: 1.25 moles
do u get it
16 x 3.75 = 60 so 3.75 moles
no punch in 40 times 3.75 and then divide by 120 you should get 1.25
oh i got 2.75
i multiplied wrong then
one second
ok i got 3.75 now
ok i got 1.25
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