Question

Evaluate the integral by interpreting it in terms of areas.

Answer 1

\[\int\limits_{-1}^{3}(6-x)dx\]

Answer 2

\[\int\limits_{-1}^{3}6dx + \int\limits_{-1}^{3}xdx\]

Answer 3

I mean minus.. but yeah

Answer 4

I'm still really lost in this equation.. :[ wouldn't x just become 1 ? so it'll become 6-1?

Answer 5

I'll start you off

Answer 6

\[\int\limits_{}^{}6dx = 6x + C, \int\limits_{}^{}xdx = x^2/2\]

Answer 7

Since you now know the indefinite integrals, you can compute

\[\int\limits_{-1}^{3}6dx - \int\limits_{-1}^{3}xdx\]

Answer 8

sorry, I'm still trying to calculate what you typed. It's going to take me a few minutes

Answer 9

i got 2?

Answer 10

4?