hhelp plz ill post the document.. its urgent please. 1. find a function of the form y= c+asin[w(t-b)] for hare population 2. find a function of the form y= c+asin[w(t-b)] for lynx population 3. add the two function together to get a new function and find the average, amplitude, period and a sine phase shift.
@ hero help plz satelite not online :d
i know that for the hares population, the amplitude is 2000, the period is pie over 125 and i dont see any phase shift
The amplitude is half the measure from peak to peak. (3500 - 500) / 2 = 1500 a = 1500
isnt amplitude the max?
amplitude is the max oscillation about the mean. because of c, the curve is shifted up and so the max will be bigger than the amplitude.
The distance between the lowest points is: 210 - 90 = 120 which is the period. So the cycle repeats itself every 120 weeks. period = 2pi/w = 120. So w = 2pi/120 = pi/60.
y = c + a * sin[w(t-b)] y = c + 1500 * sin[pi/60(t - b)] when t = 0, y = 2000 2000 = c + 1500 * sin[-pi/60 * b]
when t = 90, y = 500 500 = c + 1500 * sin[-pi/60(90 - b)] 2 unknowns, 2 equations. solve for c and b
im still confused sorry
subtract second equation from first. that will eliminate c. you can solve for b.
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I am beginning to think that c is simply 2000 because it lifts the sine wave which has a zero y intercept by 2000 to give it a y-intercept of 2000. So c may simply be 2000.
If we put c = 2000 in 2000 = c + 1500 * sin[-pi/60 * b] we get 2000 = 2000 + 1500 * sin[-pi/60 * b] 1500 * sin[-pi/60 * b] = 0 sin[-pi/60 * b] = 0 -pi/60 * b = 0 (or pi) b = 0 or ...
sorry but i give up ill talk to my prof tomorrow cuz this is too hard
ok. do you have the answer?
yeh
I think y = 2000 + 1500 * sin(pi/60 * t) for the hare population.
what is the answer?
I put a few select values of t in the above equation and it gives the y-values correctly. You don't want to give the answer?
im trying really but i just cant get it
No I meant answer form the back of the text book or multiple choice answers.
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