Question

State the phase shift of the function.

y=10sin(theta over 4 -4pi) -5

Answer 1

4pi right

Answer 2

thank you, but wouldn't you have to divide the 4pi by 1/4? @ECE

Answer 3

Probably, depends what kind of eqn you're using

Answer 4

does it really say
\[\sin(\frac{\theta}{4}-4\pi)\]?

Answer 5

if it does, then there is no phase shift, because sine is periodic with period \(2\pi\) and so
\[\sin(\frac{\theta}{4}-4\pi)=\sin(\frac{\theta}{4})\]

Answer 6

If it's in the form \[Asin(\omega*t + \theta) \]
then yea 4pi right

Answer 7

i guess what i am trying to say is that there is no such thing as a phase shift of \(4\pi\) or any integer multiple of \(2\pi\)

Answer 8

yes @satellite73 it does say that

Answer 9

ok then there is no phase shift

Answer 10

i mean it says y=10sin(theta over 4-4pi)-5 @satellite73