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what is the derivative of f(x)=2sqrt(x+(1/4))?
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\[2\sqrt{x+\frac{1}{4}} = 2 \frac{d}{dx} [x+\frac{1}{4}]^{\frac{1}{2}}\] does that help? You'll be using power and chain rule.
so it would be \[f'(x)=\frac{ 1 }{ x+\frac{ 1 }{ 4 } }\] ?
shoot that's not what i meant. i meant for the x+1/4 to be under a square root
yes.
awesome, thank you so much!
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