In ΔPQR shown below, segment QS is an altitude: What property or definition is needed to prove that ΔPSQ is similar to ΔQSR?
Transitive Property of Equality Reflexive Property of Equality Definition of an Altitude Definition of Supplementary Angles
http://learn.flvs.net/webdav/assessment_images/educator_geometry/v15/module05/05_10_b19.jpg
|dw:1386126161323:dw| like that?
yes
ok i think its reflexive property of equality because angle QSR is congruent to angle QSP because they are both 90 degrees. QS bisects angle PQR so angles SQR and PQS are congruent. therefore; angle QSR equals angle QSP angle PQS equals RQS so angle QRS must equal angle QPS all angles are equal so the triangles must be similar
see how this is the reflexive property?
because it shows how angles are equal
Also just by the definition of an altitude
i think the best answer is the definition of an altitude but the second choice is also good
yes i saw that but can you please explain how this makes the angles equal
i did look at my first post
read carefully what i wrote
basically you can prove that the angles in both the triangles are equal so they are similar
an altitude always splits an angle in 1/2
now do you get what i wrote?
yes thank you so much
ok hope i helped
you don't know what a life saver you are :)
remember it can be definition of altitude or reflexive property
i think if you choose one just tell your teacher how you proved it
yes i will
my teacher is very understanding
Reflexive Property of Equality, is incorrect.
@swifty what was the answer
Join our real-time social learning platform and learn together with your friends!