Question

How do you find the restrictions for x^2-9/x^2+3x+2

Answer 1

When there are restrictions, look at the denominator; you can't divide by 0. In this case, the denominator is (x^2+3x+2). Factor it out so it is easier (x+1)(x+2). Get each of those will equal 0; x=-1 and x=-2.
Therefore, since the domain restrictions are x=-1,-2, the domain can be all real numbers, except -2 and -1.

Answer 2

You eliminate the values that cause the denominator to be 0

Answer 3

\[\sqrt[3]{-27}\]