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Function f is continuous on the interval [-5,5] and the definite integral of f(x)dx from 0 to 5 is 4. What is the integral of f(x+2)dx from -2 to 3
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I figured to set u=x+2 but I don't know what to do after that.
\[\int_0^5 f(x)~dx=4\] Note that \(f(x+2)\) is \(f(x)\) shifted to the left by 2 units. If you did the same to the interval, you'd get \([0-2,5-2]\), or \([-2,3]\), which means \[\int_0^5 f(x)~dx=\int_{-2}^3f(x+2)~dx=4\]
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