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Mathematics 9 Online
OpenStudy (anonymous):

ou place a cup of 210oF coffee on a table in a room that is 68oF, and 10 minutes later, it is 200oF. Approximately how long will it be before the coffee is 180oF? Use Newton's law of cooling http://i.imgur.com/KCuZlK4.png 1 hour 35 minutes 15 minutes 45 minutes

OpenStudy (anonymous):

Maybe 15mins...

Directrix (directrix):

I have closer to 35 minutes but need to run the formula through again. (My working answer is 32.5 minutes.) I used this to find the cooling constant: 200 = 68 + (210 - 68)*e^(-10k) and then this equation for the time of cooling to 180 ° F 180 = 68 + (210 - 68)*e^(-.0073025t)

OpenStudy (alekos):

i got the same thing

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