Question

Can anyone help me to understand derivatives of trigonometric functions ?

Answer 1

Well you at least have to memorize \(\dfrac d{dx}\sin x=\cos x\) because the proof is very complicated

Answer 2

Then you can go like this \(\dfrac d{dx}\cos x=\dfrac d{dx}\sin\left(\dfrac\pi2-x\right)=-\cos\left(\dfrac\pi2-x\right)=-\sin x\)

Answer 3

and you can use quotient rule to work out \(\dfrac d{dx}\tan x\)

Answer 4

and quotient rule to work out the csc sec and cot (1/sin or 1/cos or 1/tan)

Answer 5

sorry brb (15 mins) cya

Answer 6

i understand the rules of derivatives of trigonometric functions but when i tried to solve some examples i discovered that all of my solutions are wrong :(

Answer 7

Okay, ask away. Let's look at an example you struggled on.

Answer 8

Or you can think of it like a circle going clockwise

where clockwise is the derivatives
anti clockwise are the integrals