Question

I need someone very generous to help me on chemistry. I am very behind I really appreciated.thank you!

A compound that is composed of molybdenum (Mo) and oxygen (O) was produced in a lab by heating molybdenum over a Bunsen burner. The following data was collected:

Mass of crucible: 38.26 g
Mass of crucible and molybdenum: 39.52 g
Mass of crucible and molybdenum oxide: 39.84 g

Solve for the empirical formula of the compound, showing (or explaining in complete sentences) your calculations.

Answer 1

The difference between the mass of the crucible and the mass of the crucible and molybdenum is the mass of molybdenum. The mass of the molybdenum divided by the molar mass of molybdenum is the number of moles of molybdenum.
The difference between the mass of the crucible and molybdenum and the mass of the crucible and molybdenum oxide is the mass of the oxygen that accumulated as you oxidized the molybdenum. the difference in mass divided by the molar mass of oxygen (single atom) is the number of moles of oxygen (single atom) that were added.
This tells you how many moles of oxygen it takes to oxidize that number of moles of molybdenum.
Do ^^^ that, then look up what empirical formula is if you don't know already.

Answer 2

ok so that will be the answer?

Answer 3

yeah i know what is the formula which is 25.6 g CO2 ((1 mole CO_2)/(44 g CO_2 )) ((6.02 X 10^23 atoms CO_2)/(1 mole CO_2 )) = 3.50 X 1023 atoms CO2 not sure