Question

An artist is creating a mosaic that cannot be larger than the space allotted which are 4 feet tall and 6 feet wide. The mosaic must be at least 3 feet tall and 5 feet wide. The tiles in the mosaic have words written on them and the artist wants the words to all be horizontal in the final mosaic. The word tiles come in two sizes: The smaller tiles are 4 inches tall and 4 inches wide, while the large tiles are 6 inches tall and 12 inches wide. If the small tiles cost $3.50 each and the larger tiles cost $4.50 each, how many of each should be used to minimize the cost? What is the minimum cost?

Answer 1

@amistre64 Need your Help Please

Answer 2

ok 0 small tile, 6 large tiles; minimum cost $27

Answer 3

i dont need answers only

Answer 4

i need how to solve it so that i can do it myself

Answer 5

with steps

Answer 6

ok If you calculate the price per square inch of the small word tiles and the large word tiles, you'll see that the large word tiles are much cheaper per square inch. Therefore, it will be much cheaper to cover with all large word tiles. The only problem that could occur is if the large tiles are of a size that is not divisible into the dimensions of the entire mosaic, but in this case they are, so just use large tiles. 4 ft x 6 ft = 24 sq ft = 2160 sq in. 6 in. x 12 in. = 72 sq in. (2160 sq in. / 72 sq in. = 135 large tiles

Answer 7

is this better @Yacoub1993