Question

PLEASE HELP!! (ATTACHMENT)

Answer 1

if a function f is continuous on the closed interval [a, b], where a < b, and differentiable on the open interval (a, b), then MVT is applicable
(per wikipedia http://en.wikipedia.org/wiki/Mean_value_theorem)

Answer 2

I know it's applicable but I don't my answer is right

Answer 3

I got c=-1

Answer 4

just to butt in, it is always the case that the "\(c\)" guarenteed to exist by the mvt is smack dab in the middle of the interval for any quadratic function

Answer 5

they want all c's where df(c)/dx = (16 - 36)/10 = -2

Answer 6

so c=-2 not -1?

Answer 7

so without doing any work, i know your answer of \(-1\) is correct, since it is in the middle of the interval \([-6,4]\)

Answer 8

f' = 2x
2x = -2
x = -1

I get -1

Answer 9

ok thank you, i just didnt think my work was right!