Question

help?

Answer 1

you are trying to find area right what is the formula?

Answer 2

i have to find the value of sine for <a

Answer 3

Ooo yikes haven't learned that yet...sorry.

Answer 4

Did you mean side or sine?

Answer 5

its ok thanks for the help :)

Answer 6

sine as in trigonometry

Answer 7

Oh lol im only in algebra 1 :D

Answer 8

Oh i see if you ever need help contact me i can help in that

Answer 9

Will do thanks!

Answer 10

Your welcome

Answer 11

what are you being asked \(\sin(A)\) ?

Answer 12

I have to find the value of sine a

Answer 13

ok then
\[\sin(A)=\frac{a}{12}\] as it is "opposite over hypotenuse"
what you are missing is the value of \(a\) which you find via pythagoras

Answer 14

you know how to find \(a\) ?

Answer 15

okay
no i dont

Answer 16

pythagoras has \(a^2+b^2=c^2\) which in your example is \(a^2+8^2=12^2\)

Answer 17

oh yes

Answer 18

this is \[a^2+64=144\] so \[a^2=144-64=80\] and therfore \[a=\sqrt{80}\]

Answer 19

alright

Answer 20

you probably want to write \[\sqrt{80}=4\sqrt5\]so you can get a better answer than \(\frac{\sqrt{80}}{12}\) and instead write
\[\sin(A)=\frac{\sqrt{5}}{3}\]

Answer 21

where did you get 80 from?

Answer 22

\(12^2=144\) and \(8^2=64\) and \(144-64=80\)

Answer 23

oh ok 144-64

Answer 24

notice that it would be easier to get rid of common factors first and look at the triangle as this

Answer 25

yes i think i understand

Answer 26

with a little practice you will get \(a\) right away as
\[a=\sqrt{3^2-2^2}=\sqrt{9-4}=\sqrt{5}\]giving
\[\sin(A)=\frac{\sqrt5}{3}\]

Answer 27

okay so say instead on sine we have cotangent. would i solve the problem the same way?

Answer 28

or do i not use the Pythagorean theorem?

Answer 29

cotangent is "adjacent over opposite"
once you have all sides, then you can find any ratio you like, assuming you know what ratio you are looking for

Answer 30

okay so my next question is the same only the hypotenuse is 10 instead of 12

Answer 31

so its a^2+8^2=10^2?

Answer 32

so it would them be 100-64=36

Answer 33

@satellite73

Answer 34

im now solving for the value of the cotangent