Question

MEDAL GIVEN TO CORRECT ANSWER.
You shoot a model rocket into the air with a speed of 18.2 m/s. How high does the rocket go?

A. 16.9 m
B. 0.93 m
C. 8.2 m
D. 4.5 m

Answer 1

Ok, that's simple. You are given the initial velocity v1 = 18.2 m/s, the acceleration due to gravity a = -9.8 m/s. Since the rocket is launching upward against gravity, the value of g will be negative.

From your question, it looks like you want to find the max. Height the rocket reaches. At max. Height for a moment the final velocity v2 will be 0 m/s.

V1 = 18.2 m/s
a= -9.8 m/s^2
V2 = 0 m/s

Since we don't have the time, use one of the big five kinematic equations to solve for the height by using the given values.

Good luck!




( in the first paragraph, I meant to say a = -9.8 m/s^2)

Answer 2

so, what equation would I use?

Answer 3

@coolsday

Answer 4

V2^2 = v1^2 + 2ad

Answer 5

Isolate d from the formula to find the max. Height

Answer 6

The five equations should be in ur notes or textbook

Answer 7

so, is the answer A? @coolsday

Answer 8

Correct