Question

Simplify:
(-xy^0x^6a^5)^-3

Answer 1

\[n^a\cdot n^b=n^{a+b}\] \[\left( n^a \right)^b=n^{ab}\] \[n^0=1, n\neq 0\]

Answer 2

Those are the three laws you'll need

Answer 3

I'd start by getting rid of the y term, then multiply the -3 exponent in

Answer 4

Okay so I got here:

(-xy^0x^6a^5)^-3
(-x^7y^0a^5)-3
Is that right so far?

Answer 5

yep so far so good

Answer 6

wait hang on
that -3 is still an exponent, you're missing a ^

Answer 7

probably just a typo though right? :)

Answer 8

Yup, thanks :) Okay so..

Answer 9

Now I have to distribute the -3 to everything

Answer 10

make your life easier first; what's y^0?

Answer 11

It's 1

Answer 12

right, so you can essentially just drop that term, since it's just multiplying stuff by 1 inside the brackets

Answer 13

Okay so:
(-1)^-3, (1)^-3, (a^5)^-3 right?

Answer 14

\[\left( -x^7a^5 \right)^{-3}=\left( \left( -1 \right)^{-3}x^{7\cdot -3}a^{5\cdot -3} \right)\]

Answer 15

that's multiplication in the exponents, it's not super clear on my screen maybe i should have used brackets

Answer 16

I am so confused. What did I do wrong?

Answer 17

i'm not sure what you were doing when you said
(-1)^-3, (1)^-3

but (a^5)^-3 was correct, you just also needed to account for (x^7)^-3

Answer 18

Okay so:
3x^14a^-10

Answer 19

how did you get 3, 14, -10?

Answer 20

You said above:
((-1)^-3x^-7*-2a^5*-2)

Answer 21

So i simplified it.

Answer 22

\[-1^{-3}=-1\]

Answer 23

\[\left( x^7 \right)^{-3}=x^{7(-3)}\]

Answer 24

\[\left( a^5 \right)^{-3}=a^{5(-3)}\]

Answer 25

does that make sense to you?

Answer 26

-1x^-14a^-10 ?

Answer 27

what's 7 times -3?

Answer 28

and 5 times -3

Answer 29

that loos like it says -2

Answer 30

ah the font on this site sucks XD

Answer 31

-1x^-15a^-21

Answer 32

lol \[\Large -x^{-21}a^{-15}\]

Answer 33

i figured it out, you do \Large in the equation :D

Answer 34

are you confused now or did that help

Answer 35

cause we can talk about exponents some more in a simpler approach

Answer 36

oops i switched them :P

Answer 37

ya it's k :)
you had the right idea i just confused you with that tiny exponent font

Answer 38

Okay so I cant let them have negitives. So:
1/x^21a^15 right? \[\frac{ 1 }{ x^21a^15 }\]

Answer 39

put your exponents in curly brackets

Answer 40

*x^21a^15

Answer 41

and remember your term is negative

Answer 42

\[\frac{ -1 }{ x^{21}a^{15} }\]

Answer 43

Yup! Got it! Thanks so much!

Answer 44

my pleasure