Question

solve each system by elimination.
3x+y=-26
2x-y=-19
what would be X and Y

Answer 1

first, change the value of y
2x-y=-19
y=2x+19

Answer 2

second, replace y in 3x+y=-26
3x+(2x+19)=-26

Answer 3

\( \begin{array}{llll}
3x+y=-26\\
2x-y=-19\\
\hline\\
5x+0y=-45
\end{array}\bf\implies 5x=-45\) solve for "x", what do you get?

Answer 4

for x you would get -9 but i can't get something for y that works for both equations

Answer 5

it will find x, then replace the value of x you have got to 2x-y=-19
you will have y
happy to help...

Answer 6

well, now that we know that x = -9, plug that in either equation, say the 1st one, so \(\bf 3x+y=-26\implies 3(-9)+y=-26\implies y=?\)

Answer 7

Don't you -27 to -26 an then that would be y

Answer 8

i mean add -27 to -26 and then that would be y

Answer 9

\(\bf 3x+y=-26\implies 3(-9)+y=-26\implies -27+y=-26\\ \quad \\
\cancel{+27-27}+y=-26+27\)

Answer 10

so y would be 1 right

Answer 11

yeap

Answer 12

\(\begin{array}{llll}
3x+y=-26\\
2x-y=-19\\
\hline\\
5x+0y=-45
\end{array}\bf\implies 5x=-45\)

notice, we already has a +y and -y right on top on one another, so we just "elimiinate" it, thus

Answer 13

okay i see that know thank you very much that helped a lot

Answer 14

yw