Question

quick question when solving for a variable ..

Answer 1

yes?

Answer 2

\[x^2 + y^2 = 4 \]

Answer 3

that's a circle

Answer 4

okay so ill be solving for y , but do i square root both sides to get x & y alone \[x + y = 2\]
and then move x to the other side or do i move \[x^2\] to the other side and THEN square root both sides to get x & y alone ?

Answer 5

you don't want to take the root of both sides

Answer 6

do i make sense ? haha

Answer 7

but i need to leave y alone , i cant have it squared

Answer 8

if it was (x+y)^2 = 4 then you would square root both sides but it's not like that
you have to solve for x and y at the same time, which is actually pretty simple

Answer 9

no i have to solve for y

Answer 10

so then what is y = to?

Answer 11

thats the thing , i have to get y alone

Answer 12

@agent0smith

Answer 13

how do you get it alone? you should have learned this in algebra

Answer 14

i know how to do it im just asking when should i take the square root of each side ? before moving x^2 to the other side or after ive moved it ?

Answer 15

you tell me, that's algebra. don't forget about pemdas

Answer 16

omg nvm .....................................

Answer 17

\[\large x^2 + y^2 = 4\]subtract x^2 from both sides first.

Answer 18

now you just gave her the answer... how did that help her

Answer 19

i always subtract it first before taking the square root ?

Answer 20

Yep. I gave her the answer. You are quite helpful.

Answer 21

why would you subtract it first?

Answer 22

You have to *isolate* y^2 before you can take a square root.

Answer 23

thats all i needed to know , i know how to do the problem i just needed clarification ....

Answer 24

oh ok thank you

Answer 25

do you understand the reason why you have to subtract it first?

Answer 26

yes because @agent0smith says so (-:

Answer 27

well then there you have it. happy homework

Answer 28

@hkim i understand what you're trying to do, but you're not doing it in the most helpful way here.

Answer 29

happy day sir !

Answer 30

(:

Answer 31

i just want others to learn to help themselves than rely on the help of others

Answer 32

That's reasonable to a point.

If it were entirely true, why would teachers exist?

Answer 33

a teacher would teach a man to fish, not get a fish for him

Answer 34

Look back through your posts in this thread and think about how helpful they are.

Answer 35

as helpful as they were received it seems like

Answer 36

same with yours, no?

Answer 37

Mine actually helped. I explained why she had to get y alone to take the sqrt.

Answer 38

i really hope she did understand the reason for that. if she did, then i'm glad you were able to help her more than i was able to

Answer 39

"you have to solve for x and y at the same time, which is actually pretty simple"
"so then what is y = to?"
"how do you get it alone? you should have learned this in algebra"
"you tell me, that's algebra. don't forget about pemdas"

Do these really look helpful when she kept asking you the same question?

Answer 40

i never said my answers were more or less helpful. obviously yours were more helpful than mine so why do you deem it necessary to copy-pasta all posts i left previously?

Answer 41

Because of this "i just want others to learn to help themselves than rely on the help of others". If someone keeps asking you the same question, then they're asking for help, because they can't help themselves (yet).

Answer 42

the degree of helpfulness of one another's answers isn't my goal or focus. i just want the person that asked the question to truly understand what was done and why it was done that way. rather than memorization, learning to find answers is my focus. maybe you might think they can't help themselves, but maybe that's where the polarity between us comes into play

Answer 43

I understand what you mean, but, you kinda need to pay attention to the asker. I could tell you were frustrating her and not helping her.

Answer 44

Someone who's getting increasingly frustrated isn't going to learn how to find answers.