Question

4x^-2y^-4z^-3 divided by 12x^-5y^-4z^2

Answer 1

^ is the exponent sign. Can you re-type it a bit clearer with more brackets?

Answer 2

@jama333 do you know how to solve this system of equations using elimination
-4x-2y=12 and 4x+8y=-24

Answer 3

the choices a.(5,3) b.(-6,-6) c.(3,1) d.(6,-6)

Answer 4

First you simplify each equation. The first one can be divided by 2 to get -2x-y=6
The second one can be divided by 4 to get x+2y=-6

Answer 5

^ means there powers, what about those?

Answer 6

\[4x ^{-2}y ^{4}z ^{-3} \div 12x ^{-5}y ^{-4}z ^{2}\]

Answer 7

I solved the two equations, but I get (-2,-2) which isn't one of your choices. Are you sure you typed the two equations correctly.
You typed. -4x-2y=12 and 4x+8y=-24

As for the other comment, yes this (^) symbol means powers of exponents. When you typed it in the initial post, you typed: 4x^-2y^-4z^-3 divided by 12x^-5y^-4z^2
If all of the exponents are negative except the z^2, then I know what to do. I just wanted to make sure you typed it right.

Answer 8

I just corrected it..if that makes it easier

Answer 9

Okay so for the first term, leave the 4y^4 in the numerator and put everything else in the denominator. When you put it in the denominator, it is no longer a negative exponent.
So the first term becomes (4y^4) / [(x^2)(z^3)]

Answer 10

The second term becomes (12z^2) / [(x^5)(y^4)].

Answer 11

So remember that x^(-2) = 1/(x^2)

So now that we've gotten rid of the negative exponents, it's easier to deal with it.
When you multiply by a fraction, it's the same as dividing by its reciprocal.
The reciprocal of 2/3 is 3/2.

Answer 12

(4y^4) / (x^2)(z^3) TIMES (x^5)(y^4) / 12z^2

Do you know you to cancel stuff?