MIT 6.002 Circuits and Electronics, Spring 200721 Online
OpenStudy (anonymous):
please help me with Fall 2013 midterm exam Q6(all)
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OpenStudy (anonymous):
what about the Q1 to Q5 ??
OpenStudy (anonymous):
Can you give me the answer for the above? thanks!
OpenStudy (anonymous):
I said Q6 because it's same expression for everyone. Have any got the expression for Vout?
OpenStudy (anonymous):
Q6 1) Vout=VS-RD*m*VS/2
2)VS*(RG+RF)/(m*RG*RD+RG+RF)
HIT BEST RESPONSE IF IT'S CORRECT.
OpenStudy (anonymous):
1)correct
2)gives incorrect
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OpenStudy (anonymous):
Q2????????
OpenStudy (anonymous):
Q6
OpenStudy (anonymous):
About Q6 the second expression you gave doesnt accept it,the first correct
OpenStudy (anonymous):
About Q2 I have different values.I only have found Q2 2)0.4
OpenStudy (anonymous):
Q3
1) 1.714
2) 2.14
3) 1
4) 0.5
sorry for the wrong numbering .DON"T FORGET TO HIT BEST ANSWER
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OpenStudy (anonymous):
can anybody tell me about Q6.-sub question 2
?
OpenStudy (anonymous):
please help Q6: subquestion 2...
OpenStudy (anonymous):
Questions Q1 and Q2 have the solution;
OpenStudy (anonymous):
@kostasmixalis :Hey then please provide an equation for Q1 and Q2.. please
OpenStudy (anonymous):
Q5.1 : 1
Q5.2 : Vil - Vol
Q5.3 : Voh - Vih
Q5.4 : Vih - Vil
Q5.5 : [(Vs*2*Ron)/(VoL)] - (2*Ron)
Q5.6 : [VS^2/(RON+RPULLUP)]
For Q5.6 multiply it with 1000 because they demand in mWatts.
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OpenStudy (anonymous):
Hey post some equation for Q1 and Q2.. please I am stuck with that.. please..
OpenStudy (anonymous):
What is RPULLUP?
OpenStudy (anonymous):
RPULLUP = RL
OpenStudy (anonymous):
is it RL no?
OpenStudy (anonymous):
Ok thanks
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OpenStudy (anonymous):
Hey, thanks a lot : ) Did you find an equation for Q6b?
OpenStudy (anonymous):
Nope.. Do you have an equation for Q1.1 and Q1.3 ??
OpenStudy (anonymous):
Just simulate it somewhere : )
OpenStudy (anonymous):
Plz give help for Q1whole exersice ?? Thanks
OpenStudy (anonymous):
pls help, i still dont have q2 and q7
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OpenStudy (anonymous):
Q7
1) 3.358
2) 2.798
3) 1
OpenStudy (anonymous):
How can we approach Q1?
OpenStudy (anonymous):
for q1.1 just find the v/g at A and B.then find the differntial voltage,tat gives ur Vth,,then find norton current equivalent,,simply IN=Vth/Rth
OpenStudy (anonymous):
Plz give help for Q1whole exersice ?? Thanks
OpenStudy (anonymous):
Q2 2)0.4
3)1.8
4)0.8
5)5
pls help in question 2(1,6) and 7.1 and 7.2
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OpenStudy (anonymous):
q1.3 please
OpenStudy (anonymous):
@vasw answer for Q7 is found above
OpenStudy (anonymous):
Q2 1) 2.5
2) -2
HIT BEST ANSWER TO HELP OTHERS
OpenStudy (anonymous):
Q1 2) 5.64
OpenStudy (anonymous):
what about Q1.3 and Q2.6 ??
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OpenStudy (anonymous):
Q1.1: 1.232
OpenStudy (anonymous):
Q7(1,2)??
OpenStudy (anonymous):
can you tell me how you solved this? Q7 (1,2)??
OpenStudy (anonymous):
Q7.1: 4.5
Q7.3: 1
OpenStudy (anonymous):
sorry I dont have any equation.
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OpenStudy (anonymous):
Q7 (2) ??
OpenStudy (anonymous):
plz help Q1(3)??
OpenStudy (anonymous):
Q7.2: 3
OpenStudy (anonymous):
do not know about Q1.3..
do you have any idea ?
OpenStudy (anonymous):
Thanks!!! :)
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OpenStudy (anonymous):
give me an answer for Q1.3 if you have..
OpenStudy (anonymous):
Do you think if i simulate can help ? I haven't the answer! :(
OpenStudy (anonymous):
nope. simulation gives an error. I dont know why but I tried it..
OpenStudy (anonymous):
guys, if your done with q1.3 i need help
OpenStudy (anonymous):
Anybody find the value of Q1.3 ??
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OpenStudy (anonymous):
@neelshah answer for Q1.3 is 165.777181208
OpenStudy (anonymous):
@andy8 i wrote the answer above!
OpenStudy (anonymous):
Anyone got the answer for 7.2? I am missing only this...