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MIT 6.002 Circuits and Electronics, Spring 2007 21 Online
OpenStudy (anonymous):

please help me with Fall 2013 midterm exam Q6(all)

OpenStudy (anonymous):

what about the Q1 to Q5 ??

OpenStudy (anonymous):

Can you give me the answer for the above? thanks!

OpenStudy (anonymous):

I said Q6 because it's same expression for everyone. Have any got the expression for Vout?

OpenStudy (anonymous):

Q6 1) Vout=VS-RD*m*VS/2 2)VS*(RG+RF)/(m*RG*RD+RG+RF) HIT BEST RESPONSE IF IT'S CORRECT.

OpenStudy (anonymous):

1)correct 2)gives incorrect

OpenStudy (anonymous):

Q2????????

OpenStudy (anonymous):

Q6

OpenStudy (anonymous):

About Q6 the second expression you gave doesnt accept it,the first correct

OpenStudy (anonymous):

About Q2 I have different values.I only have found Q2 2)0.4

OpenStudy (anonymous):

Q3 1) 1.714 2) 2.14 3) 1 4) 0.5 sorry for the wrong numbering .DON"T FORGET TO HIT BEST ANSWER

OpenStudy (anonymous):

can anybody tell me about Q6.-sub question 2 ?

OpenStudy (anonymous):

please help Q6: subquestion 2...

OpenStudy (anonymous):

Questions Q1 and Q2 have the solution;

OpenStudy (anonymous):

@kostasmixalis :Hey then please provide an equation for Q1 and Q2.. please

OpenStudy (anonymous):

Q5.1 : 1 Q5.2 : Vil - Vol Q5.3 : Voh - Vih Q5.4 : Vih - Vil Q5.5 : [(Vs*2*Ron)/(VoL)] - (2*Ron) Q5.6 : [VS^2/(RON+RPULLUP)] For Q5.6 multiply it with 1000 because they demand in mWatts.

OpenStudy (anonymous):

Hey post some equation for Q1 and Q2.. please I am stuck with that.. please..

OpenStudy (anonymous):

What is RPULLUP?

OpenStudy (anonymous):

RPULLUP = RL

OpenStudy (anonymous):

is it RL no?

OpenStudy (anonymous):

Ok thanks

OpenStudy (anonymous):

Hey, thanks a lot : ) Did you find an equation for Q6b?

OpenStudy (anonymous):

Nope.. Do you have an equation for Q1.1 and Q1.3 ??

OpenStudy (anonymous):

Just simulate it somewhere : )

OpenStudy (anonymous):

Plz give help for Q1whole exersice ?? Thanks

OpenStudy (anonymous):

pls help, i still dont have q2 and q7

OpenStudy (anonymous):

Q7 1) 3.358 2) 2.798 3) 1

OpenStudy (anonymous):

How can we approach Q1?

OpenStudy (anonymous):

for q1.1 just find the v/g at A and B.then find the differntial voltage,tat gives ur Vth,,then find norton current equivalent,,simply IN=Vth/Rth

OpenStudy (anonymous):

Plz give help for Q1whole exersice ?? Thanks

OpenStudy (anonymous):

Q2 2)0.4 3)1.8 4)0.8 5)5 pls help in question 2(1,6) and 7.1 and 7.2

OpenStudy (anonymous):

q1.3 please

OpenStudy (anonymous):

@vasw answer for Q7 is found above

OpenStudy (anonymous):

Q2 1) 2.5 2) -2 HIT BEST ANSWER TO HELP OTHERS

OpenStudy (anonymous):

Q1 2) 5.64

OpenStudy (anonymous):

what about Q1.3 and Q2.6 ??

OpenStudy (anonymous):

Q1.1: 1.232

OpenStudy (anonymous):

Q7(1,2)??

OpenStudy (anonymous):

can you tell me how you solved this? Q7 (1,2)??

OpenStudy (anonymous):

Q7.1: 4.5 Q7.3: 1

OpenStudy (anonymous):

sorry I dont have any equation.

OpenStudy (anonymous):

Q7 (2) ??

OpenStudy (anonymous):

plz help Q1(3)??

OpenStudy (anonymous):

Q7.2: 3

OpenStudy (anonymous):

do not know about Q1.3.. do you have any idea ?

OpenStudy (anonymous):

Thanks!!! :)

OpenStudy (anonymous):

give me an answer for Q1.3 if you have..

OpenStudy (anonymous):

Do you think if i simulate can help ? I haven't the answer! :(

OpenStudy (anonymous):

nope. simulation gives an error. I dont know why but I tried it..

OpenStudy (anonymous):

guys, if your done with q1.3 i need help

OpenStudy (anonymous):

Anybody find the value of Q1.3 ??

OpenStudy (anonymous):

@neelshah answer for Q1.3 is 165.777181208

OpenStudy (anonymous):

@andy8 i wrote the answer above!

OpenStudy (anonymous):

Anyone got the answer for 7.2? I am missing only this...

OpenStudy (anonymous):

Q7 2) 3

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