(Ancient chinese problem) A band of 17 pirates stole a sack of gold coins , when they tried to devide the fortune into equal portions , 3 coins remained .In the ensuring brawl over this time an equal division left 10 coins . Again an argument developed in which another pirate was killed . but now the total fortune was evenly distributed among the survivor . what was the last number of coins that could have been stolen ?
ughhh its the same qs :| ok type the equations
x = 3 mod 17 x = 10 mod 16 x = 0 mod 15 ?
ok lets do it without using chinese
ok thats right.. now since gcd(17,16,15)=1 use chinese
why?
without chinese ok cool :)
no, i mean, what is the chinese remainder. please teach
we did chinese in last problem already, so lets do it without chinese so that we dont need to prove chinese remainder theorem here
take last congruence, x = 0 mod 15 => x = 15k
well i saw the solution already, but whats the logic behind chinese
you want to know the logic behind chinese ? or the solution to this problem, w/o using chinese ? :) cuz u were asking for a solution w/o chinese in earlier post...
i dont understnad this pellet
i am frustrated as heck
you deserve to :o
perl ok lets solve it using chinese (to intruduce u chinese thm ) then prove it so u cud see the logic of it k ??
ok
ok so u got the three equations x = 3 mod 17 x = 10 mod 16 x = 0 mod 15 sice gcd(17,16,15)= 1 u can apply chinese thm
now u got c1=3 c2=10 c3=0
ok
whats teh chinese remainder theorem?
nw u need to convert it to m x =1 mod n formulla ok ?
why?
sorry i ask a lot of questions
cuz if gcd(a,n)=1 ,then the linear congruence ax=b(mod n) has a unique sol modulo n then congruence ax=1 mod n has a unique solution this is called (multiplicasive) inverse of a modulo n
why does it need to be a unique solution
you keep saying unique solution, is this significant
lol know wat thats not me who saying its the thm check it in google :P
why do we need to change to mx = 1 mod n?
do you have a number theory book i can read
youre terrible at explaining this ,
whats next >
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