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Mathematics 12 Online
OpenStudy (anonymous):

Find the sum of the series

OpenStudy (anonymous):

\[\sum_{n=1}^{\infty} \frac{ 3^nx ^{2n} }{ 4^{n+1} }\]

OpenStudy (anonymous):

@Loser66

OpenStudy (anonymous):

Um, you're given a power series... are you supposed to find the "summing" function? Or are you looking for the radius of convergence?

OpenStudy (anonymous):

I found the radius of convergence to be 2/sqrt(3). Need to find sum S of the series.

OpenStudy (anonymous):

@Hero

OpenStudy (anonymous):

you need to find a way to sum up a power series...I am sure your book has some suggestions yes?

OpenStudy (anonymous):

Okay, well try comparing it to the following, \[\frac{1}{1-x}=\sum_{n=0}^\infty x^n\] \[\begin{align*}\sum_{n=1}^\infty \frac{3^nx^{2n}}{4^{n+1}}&=\frac{1}{4}\sum_{n=1}^\infty \left(\frac{3}{4}x^2\right)^n \end{align*}\] How would you write this like the first known series?

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