Question

During a softball game, a batter hits a ball upward from an initial height of 3 feet. The height, in feet, of the softball is given by \(s(t) = -16t^2+70t+3\) , where t is time in seconds and . Which is closest to the time when the softball will be 50 feet above the ground?

Answer 1

I have the possible choices of
0.66 seconds
5.03 seconds
0.83 seconds or 3.55 seconds
0.66 seconds or 5.03 seconds

Answer 2

50 = -16t^2 + 70t + 3

16t^2 - 70t + 47 = 0

solve for t

Answer 3

use t = [70 +/- sqrt(70^2 - 4*16*47)] / 32

= (70 +/- 42.66) / 32

Answer 4

Thanks I used your base idea and I figured it out :)

Answer 5

3rd option?