Question

Please help me solve for r!
r^2-4r+8=5r

Answer 1

First you should subtract 8. In order to pass it to the other side of the equation.

Answer 2

Then it should look like this r^2-4r=5r-8
Then subtract the 5r. r^2-4r-5r=-8
Once you did that you can combine the r's. so...
r^2-9r=-8

Answer 3

I did that and I got r^2 -9r +8=0
What I have so far is:

Answer 4

Okay, so next you should try to simplify the sqrt.

Answer 5

I thought 113 was prime

Answer 6

Then if it can't be simplified any more, I'm pretty sure that's your answer. I know It looks big.

Answer 7

But the actual answers are 8 and 1

Answer 8

Like the book tells me the answers are 8 and 1 and r^2 - 9 + 8 = 0 factors out to (r-8)(r-1)

Answer 9

Hmm... then I'm not too sure sorry.

Answer 10

Hold on a sec

Answer 11

if i subtracted r^2 - 4r +8 onto the side 5r is on, would i get a different answer?

Answer 12

minus both sides by 5r what do you have