A train travels between two stations 1/2 mile apart in a minimum time of 41 sec. If the train accelerates and decelerates at 8 ft/sec^2, starting from the first station and coming to a stop at the second station, what is its maximum speed in mph? How long does it travel at this top speed?

Question

anonymous · Answer

help pls

parthkohli · Answer

Let's say that the train takes $t_0$ time to reach the max. speed $v_o$. Use the equation $v_f = v_i + at$.

Then you have,$$v_0 = 8t_0$$$$0 = v_0 - 8(41 - t_0)$$

parthkohli · Answer

Two equations... two variables. Solve.

parthkohli · Answer

That is, if I understood your question correctly. The train starts, accelerates at 8 ft/sec^2, reaches the top speed, and decelerates at 8 ft/sec^2?

parthkohli · Answer

If that is so, then the other info is useless.

anonymous · Answer

the final answer should be 60mph. but i did't get the same answer ung your two equations